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Rename an index

Problem

You need to rename an index within the current database.

Solution

Use the Update function:

client.query(
  q.Update(q.Index('all_people'), { name: 'all_of_the_people' })
)
.then((ret) => console.log(ret))
.catch((err) => console.error(
  'Error: [%s] %s: %s',
  err.name,
  err.message,
  err.errors()[0].description,
))
{
  ref: Index("all_of_the_people"),
  ts: 1631909688640000,
  active: true,
  serialized: true,
  name: 'all_of_the_people',
  source: Collection("People"),
  values: [
    { field: [ 'data', 'first' ] },
    { field: [ 'data', 'last' ] },
    { field: [ 'ref' ] }
  ],
  partitions: 8
}
result = client.query(
  q.update(q.index("all_people"), {"name": "all_of_the_people"})
)
print(result)
{'ref': Ref(id=all_of_the_people, collection=Ref(id=indexes)), 'ts': 1631911056110000, 'active': True, 'serialized': True, 'name': 'all_of_the_people', 'source': Ref(id=People, collection=Ref(id=collections)), 'values': [{'field': ['data', 'first']}, {'field': ['data', 'last']}, {'field': ['ref']}], 'partitions': 8}
result, err := client.Query(
	f.Update(
		f.Index("all_people"),
		f.Obj{"name": "all_of_the_people"},
	))

if err != nil {
	fmt.Fprintln(os.Stderr, err)
} else {
	fmt.Println(result)
}
map[active:true name:all_of_the_people partitions:8 ref:{all_of_the_people 0xc0000924b0 0xc0000924b0 <nil>} serialized:true source:{People 0xc0000925a0 0xc0000925a0 <nil>} ts:1631911524480000 values:[map[field:[data first]] map[field:[data last]] map[field:[ref]]]]
try
{
    Value result = await client.Query(
        Update(
            Index("all_people"),
            Obj("name", "all_of_the_people")
        )
    );
    Console.WriteLine(result);
}
catch (Exception e)
{
    Console.WriteLine($"ERROR: {e.Message}");
}
ObjectV(ref: RefV(id = "all_of_the_people", collection = RefV(id = "indexes")),ts: LongV(1632032537300000),active: BooleanV(True),serialized: BooleanV(True),name: StringV(all_of_the_people),source: RefV(id = "People", collection = RefV(id = "collections")),values: Arr(ObjectV(field: Arr(StringV(data), StringV(first))), ObjectV(field: Arr(StringV(data), StringV(last))), ObjectV(field: Arr(StringV(ref)))),partitions: LongV(8))
System.out.println(
        client.query(
            Update(
                Index("all_people"),
                Obj("name", Value("all_of_the_people"))
            )
        ).get());
{ref: ref(id = "all_of_the_people", collection = ref(id = "indexes")), ts: 1632028348930000, active: true, serialized: true, name: "all_of_the_people", source: ref(id = "People", collection = ref(id = "collections")), values: [{field: ["data", "first"]}, {field: ["data", "last"]}, {field: ["ref"]}], partitions: 8}
Update(Index('all_people'), { name: 'all_of_the_people' })
{
  ref: Index("all_of_the_people"),
  ts: 1631835755950000,
  active: true,
  serialized: true,
  name: 'all_of_the_people',
  source: Collection("People"),
  values: [
    { field: [ 'data', 'first' ] },
    { field: [ 'data', 'last' ] },
    { field: [ 'ref' ] }
  ],
  partitions: 8
}
Query metrics:

  •    bytesIn:    82

  •   bytesOut:   350

  • computeOps:     1

  •    readOps:     0

  •   writeOps:     1

  •  readBytes: 1,587

  • writeBytes:   486

  •  queryTime: 381ms

  •    retries:     0

Discussion

You can rename an index, add metadata, or change the unique field. However, you cannot change an index’s terms or values definitions after the index has been created.

If you need to modify an index’s terms or values definition, you should create a new index with the new definition, then rename the old index out of the way, and rename the new index to use the original name of the old index.

If you change unique to true, any existing duplicate items in the index are not automatically removed.

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