DayOfYear

DayOfYear( timestamp )
DayOfYear( timestamp )
DayOfYear( timestamp )
DayOfYear( timestamp )
day_of_year( timestamp )
DayOfYear( timestamp )
DayOfYear( timestamp )

Description

The DayOfYear function extracts the day of the year from a Timestamp.

Parameters

Argument Type Definition and Requirements

timestamp

Timestamp

A timestamp.

Returns

A Number which represents the value of the day of the year, in the range 1 to 366, from the provided timestamp.

Examples

The following query returns the day of the year from a timestamp:

try
{
    Value result = await client.Query(
        DayOfYear(Time("2019-04-29T12:51:17Z"))
    );
    Console.WriteLine(result);
}
catch (Exception e)
{
    Console.WriteLine($"ERROR: {e.Message}");
}
LongV(119)
result, err := client.Query(
	f.DayOfYear(f.Time("2019-04-29T12:51:17Z")))

if err != nil {
	fmt.Fprintln(os.Stderr, err)
} else {
	fmt.Println(result)
}
119
System.out.println(
    client.query(
        DayOfYear(Time(Value("2019-04-29T12:51:17Z")))
    ).get()
);
119
client.query(
  q.DayOfYear(q.Time('2019-04-29T12:51:17Z'))
)
.then((ret) => console.log(ret))
.catch((err) => console.error('Error: %s', err))
119
result = client.query(
  q.day_of_year(q.time("2019-04-29T12:51:17Z"))
)
print(result)
119
try {
  println(Await.result(
  client.query(DayOfYear(Time("2019-04-29T12:51:17Z"))),
  5.seconds
))} catch {
  case unknown: Throwable => println("Error: " + unknown.getMessage())
}
119
DayOfYear(Time('2019-04-29T12:51:17Z'))
119

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